(X^2+380)+x=800

Solution for (X^2+380)+x=800 equation:

(X^2+380)+X=800

We move all terms to the left:

(X^2+380)+X-(800)=0

We add all the numbers together, and all the variables

X+(X^2+380)-800=0

We get rid of parentheses

X^2+X+380-800=0

We add all the numbers together, and all the variables

X^2+X-420=0

a = 1; b = 1; c = -420;
Δ = b2-4ac
Δ = 12-4·1·(-420)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-41}{2*1}=\frac{-42}{2}
=-21
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+41}{2*1}=\frac{40}{2}
=20
$